SOLUTION: For the given area, find the length and width of the rectangle with the least perimeter. Use whole numbers only.
30 m2
40 yd2
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Question 194543This question is from textbook Harcourt Math
: For the given area, find the length and width of the rectangle with the least perimeter. Use whole numbers only.
30 m2
40 yd2
This question is from textbook Harcourt Math
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
For the given area, find the length and width of the rectangle with the least perimeter. Use whole numbers only.
30 m2
40 yd2
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A square has the least perimeter for a rectangle. (A proof is available is needed.)
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For squares, P = 4*s
30 sq meters --> sides of sqrt(30) meters
l = w = sqrt(30) = ~ 5.477 meters
Using integers, --> 5 by 6.
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40 sq yds --> sqrt(40)
l = w = sqrt(40) = ~ 6.325 yards
Using integers --> 5 by 8 yards
This is a silly problem.
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