SOLUTION: Q: A rectangle has an area of 6 yards squared. If the width of the rectangle is 2/5 yards, what is the length of the rectangle? I assume that to get the 6yds sq. It was LxW as

Algebra ->  Surface-area -> SOLUTION: Q: A rectangle has an area of 6 yards squared. If the width of the rectangle is 2/5 yards, what is the length of the rectangle? I assume that to get the 6yds sq. It was LxW as      Log On


   

Question 162699: Q: A rectangle has an area of 6 yards squared. If the width of the rectangle is 2/5 yards, what is the length of the rectangle?

I assume that to get the 6yds sq. It was LxW assuming L=3 & W=2 but I do not no where to go from there?
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Not quite sure how you arrived at L = 3 & W = 2, but that is not correct.
Here's how we would find the length from the information given in the problem:
A+=+L%2AW You were correct here.
W+=+2%2F5 yds. and the area, A, = 6 sq.yds. So, we make the appropriate substitutions into the formula for the area.
6+=+L%2A%282%2F5%29 Multiply both sides by the multiplicative inverse of 2%2F5 which is 5%2F2:
%285%2F2%29%2A6+=+L%2A%282%2F5%29%285%2F2%29 Evaluate this.
15+=+L
So the length of the rectangle is 15 yards.
Check:
A+=+L%2AW Substitute L = 15 and W = 2/5
A+=+15%282%2F5%29
A+=+6 It checks!