# SOLUTION: please help!!! the robinson track is shpaed like a rectangle with a semicircle on each of the shorter sies. the distance around the track is 1/4 mile. the straightaway is twice

Algebra ->  Algebra  -> Surface-area -> SOLUTION: please help!!! the robinson track is shpaed like a rectangle with a semicircle on each of the shorter sies. the distance around the track is 1/4 mile. the straightaway is twice       Log On

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 Click here to see ALL problems on Surface-area Question 149114: please help!!! the robinson track is shpaed like a rectangle with a semicircle on each of the shorter sies. the distance around the track is 1/4 mile. the straightaway is twice as long as the width of the field. what is the area of the field enclosed by the track to the nearest square foot? thank you sooo much !Answer by josmiceli(9649)   (Show Source): You can put this solution on YOUR website!Call the straight part of the track Call the width Adding up the stright parts on each side, The straightaway is twice the width The circular portions of the track are made up of 1/2 the circumference of a circle with diameter = on one end and another 1/2 of a circumference with diameter = on the other end of the track If circumference = , also, mi 1 mi = 5280 ft ft The area of the track is made up of a rectangle and 2 half-circles which add up to a whole circle, area = The area of the rectangular part is The total area is The area of the field to the nearest ft2 is 95,077 ft2 check my work- I could have made a mistake, but I hope you get my method