SOLUTION: In square units what is the area of triangle ADB Given: Triangle ABC Triangle DBC Triangle ADB AD= 6 DC= 4 BC= 8 Angle ACB is a right angle D is a point on line AC

Algebra ->  Surface-area -> SOLUTION: In square units what is the area of triangle ADB Given: Triangle ABC Triangle DBC Triangle ADB AD= 6 DC= 4 BC= 8 Angle ACB is a right angle D is a point on line AC       Log On


   

Question 148398: In square units what is the area of triangle ADB
Given:
Triangle ABC
Triangle DBC
Triangle ADB
AD= 6
DC= 4
BC= 8
Angle ACB is a right angle
D is a point on line AC

I tried to insert the picture but i couldn't sorry


Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
If "ACB" forms a right triangle, you should have the following sides:
"AC"= opposite side
"CB"= adjacent side
"AB"= hypotenuse side
Now, there's a point in line "AC" called "D" and forms an obtuse triangle "ADB"-----> unknown Area?
.
Area=(1/2)*base*height -----> working equation
.
We have to remember that the "base" is always perpendicular to the "height" for the equation to work. The "base" is given which is "AD"= 6, but we can't use "DB" as height bec. is not perpendicular to "AD" right?
.
If you extend line AD to C meets line "BC" and forms 90 degree. Very good! As it is given, "BC"= 8 and we'll be the height of triangle "ADB".
Going back to our working eq'n,
A=%281%2F2%29base%2Aheight=%281%2F2%29%28AD%29%28BC%29
A=%281%2F2%29%286%29%288%29
A=24+square+units
Thank you,
Jojo