SOLUTION: The lenght of a rectangle is 3 cm greater than the width. If each dimension is increased by 2cm, the area is increased by 26 cm squared. Find the orginal dimensions of the rectan
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Question 131750: The lenght of a rectangle is 3 cm greater than the width. If each dimension is increased by 2cm, the area is increased by 26 cm squared. Find the orginal dimensions of the rectangle.
Please send the problem in linear form to Kathy.Christensen@wowway.com
Thank you
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Let x= width
x+3= length
x(x+3) = original area
x+2= increased width
x+3+2=x+5= increased length
(x+2)(x+5)= larger area
x^2+7x+10 = larger area
Original area + 26 = Larger area
Subtract from each side
width
length
Original rectangle= 4x7=28 sq cm
Increased rectangle = 6x9=54 sq cm
Check: Difference in the area is 26 sq cm.
R^2
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