The perimeter is (5 + 5) + (6+6) +  =  = 34.5663706 m.


The area is the sum of the areas of two right-angled triangles PLUS the area of the rectangle 
PLUS the area of the semi-circle of the radius 8/2 = 4 m


Right angled triangles are (3-4-5)-triangles. The area of each such triangle is (1/2)*3*4 = 3*2 = 6 m^2.


So, the area under the question is 

    2*6 + 6*8 +  =  = 85.1327412 m^2.

The triangle at the top has: 


Its two slanted sided contribute 2(5m) = 10m to the perimeter.

The rectangle in the middle has:


It's left and right sides contribute 2(6m) = 12m to the perimeter.

The semi-circle at the bottom has diameter 8m and therefor 4m radius:
 m2.

It contributes  m to the circumference.

 m2

 m.

Edwin