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ABCDEF is a regular hexagon, and PQR is an equilateral triangle.
Find the ratio of the area of the triangle to the area of the hexagon.
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Let r be the side of the hexagon ABCDEF.
Then the area of the hexagon is the area of 6 equilateral triangles with the side "r"
area of the hexagon = .
Regarding the triangle PQR, its side is, OBVIOUSLY, arithmetic mean of r and 2r
(its side is the mid-line of the trapezoid CDEB).
So, the side of the triangle PQR is a = = 1.5r.
Then the area of the triangle PQR is = .
Thus the ratio of the area of the triangle to the area of the hexagon is
= = = = . ANSWER
Solved, with complete explanations.