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A square piece of tin is made into an open box by cutting a 9 cm square from each corner.
The volume of the box is 3249 cm3. What was the area, in cm^2, of the original piece of tin?
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The height of the box is = 3 centimeters.
Therefore, the base area of the box is the volume divided by the height
base area = = 1083 cm^2.
Hence, the side of the base is = 32.909 cm (approximately).
Then the size of the original square piece of tin is 32.909 + 3 + 3 = 38.909 cm.
ANSWER. The size of the original square piece of tin is about 38.909 cm.
CHECK. The volume of the box is = 3249.007 cm^3, which is approximately right.
Solved.