Let x be the Janette age at the wedding year.

Then the Fidel's age was   at this year.


On their golden wedding anniversary, the Janette age will be (x+50) years, while the Fidel's age will be .


We have this equation then


     = .


To solve it, first multiply both sides by GCD of 14; then simplify


    3*7*x + 700 = 2*8*(x+50)

     21x  + 700 = 16x + 800

     21x - 16x  = 800 - 700

        5x      =    100

         x      =    100/5 = 20.


ANSWER.  At marriage, Janette was 20 years old;  Fidel was   = 30 years old.

Let Janette's age, on their wedding day, be J
Then Fidel's, on their wedding day was: 
Janette's age, on their golden anniversary, will be: J + 50 
Fidel's age, on their golden anniversary, will be: 
We then get: 
21J + 700 = 2(8)(J + 50) ------ Multiplying by LCD, 14
21J + 700 = 16J + 800
21J - 16J = 800 - 700
5J = 100
Janette's age, on their wedding day, or: 
Fidel's age, on their wedding day, was: 
You now can easily find their ages on their golden anniversary.