SOLUTION: In the figure at right, segment AB is the diameter of the large circle. Points X and Y are the centers of the small circles that have equal radii and are tangent to both each othe

Algebra ->  Surface-area -> SOLUTION: In the figure at right, segment AB is the diameter of the large circle. Points X and Y are the centers of the small circles that have equal radii and are tangent to both each othe      Log On


   

Question 1177108: In the figure at right, segment AB is the diameter of the large circle. Points X and Y are the centers of the small circles that have equal radii and are tangent to both each other and to the larger circle. What is the ratio of the area of the shaded region to the area of the large circle?
Don't know how to get the picture in here,you can maybe right it down or visualize. AB has a Over bar above it
Answer by ikleyn(52810) About Me  (Show Source):
You can put this solution on YOUR website!
.

HINT


The radius of the large circle is two times the radius of the small circle,
        which is OBVIOUS.


So,

        the area of one small circle is  pi%2Ar%5E2.

        the area of the other small circle is  pi%2Ar%5E2,  too;

        the total area of the two small circles is  2%2Api%2Ar%5E2;

        and the area of the large circle is  pi%2A%282r%29%5E2 = 4pi%2Ar%5E2.


Having this info delivered to you,  can you make the last simple step to complete the job ?