What is the area of the figure bounded by x = -3, x = 2, y + 4 = (-2/5)(x - 2), and 5y - x - 13 = 0 when graphed on a coordinate plane?
When plotted, the graphs of:
a) and x = - 3 intersect at the point (- 3, 2)
b) and x = - 3 intersect at the point (- 3, - 2)
c) and x = 2 intersect at the point (2, 3)
d) and x = 2 intersect at the point (2, - 4)
These four points form a trapezoid, with a height of 5 (2 - - 3), as seen on the x-axis
With the trapezoid's shorter base being 4 [from (- 3, 2) to (- 3, - 2)] units, and longer base being 7 [from (2, 3) to (2, - 4)],
we then get the trapezoid's area or the area bounded by the four line graphs as: