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Let x be the length of the side of the base, and
let y be the height of the container.
Then the volume is = 18000 cubic inches.
The cost of the material for two bases is dollars;
the cost of the material for four lateral sides is 4*3*x*y = 12xy dollars.
The problem requires us to minimize = 18000.
Using the restriction formula, express y = and substitute it into the total cost expression.
Then the cost takes the form C(x) = = .
Thus the problem is just reduced to finding minimum of the function
C(x) = .
To find it minimum, take a derivative and equate it to zero. It gives you the equation
C'(x) = = 0,
which implies
4x^3 = 216000,
x^3 = 54000
x = = .
Then y = = = .
ANSWER. x= = 37.798 inches (approximately) and y= = 12.6 inches (approximately).
PARTIAL CHECK. = = 18001 in^3. The miserable difference is due to rounding.
Solved.