SOLUTION: What is the maximum amount of fencing needed to construct a rectangle enclosure containing 1800 ft^2 using a river as a natural boundary on one side?

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Question 1146865: What is the maximum amount of fencing needed to construct a rectangle enclosure containing 1800 ft^2 using a river as a natural boundary on one side?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Dimensions x and y;



------------mistake here-----the rest needs to be fixed-------


--------------NO-----------based upon above mistake--------------------------






Find x value for .



36*2*10*10
2*3*2*3*2*2*2*5*5
(2^5*3*5^2)
(2^3*2^2)(75)

-



If no mistakes made, the total length of fencing:

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.

            Regarding this post,  I have two notices.


1.   Your formulation is  INCORRECT.

      The question should ask about the  MINIMUM  length of the fencing ---- NOT about the maximum length.
      The maximum length  DOES  NOT  EXIST.   You can make your enclosure longer and narrower,  by keeping the same area.

      The correct formulation is  THIS :

  
           What is the  fencing length needed to construct a rectangle enclosure 
           containing 1800 ft^2 using a river as a natural boundary on one side? 


2.   The "solution" by @josgarithmetic is   TOTALLY   WRONG,  starting from its third line to the end.

      So you better simply  IGNORE  it.


      Below find my correct solution.


xy = 1800              (1)

x + 2y -----> minimize        (x is the length along the river)



So your task is to minimize (x+2y) under the given condition/restriction  (1).



From (1),  x = ,  so we need to minimize the function  f(y) = .


The derivative  f'(y) = - + 2.


To find the minimum of f(y), equate its derivative to zero


    - + 2 = 0


     = 2

     =  = 900

    y =  = 30.


ANSWER.  The minimum fencing is at y = 30 ft perpendicular to the river and x =  =  = 60 ft along the river.

Solved.


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