SOLUTION: An oval track is made by enclosing semicircles on each end of a 48 m by 96 m rectangle. Find the area enclosed by the track. Use 3.14 for pi.

Question 1132919: An oval track is made by enclosing semicircles on each end of a 48 m by 96 m rectangle. Find the area enclosed by the track. Use 3.14 for pi.

Found 3 solutions by Alan3354, ikleyn, MathLover1:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
An oval track is made by enclosing semicircles on each end of a 48 m by 96 m rectangle. Find the area enclosed by the track.
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You didn't say which ends have the semicircles.
I'll do it for the 48 m wide ends:
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Area of the rectangle = 48*96 sq meters
Area of the 2 semicircles = pi*24^2 sq meters
Add the 2 areas.
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Ikelyn's answer makes no sense.
And I quote:
"Area enclosed by the track = 48*96 + pi*(48/2)^2 + pi*(24/2)^2 square meters."
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But, it's educational to get different "answers" and then figure out which might be correct.
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Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.

Area enclosed by the track = 48*96 + + square meters. You do the rest.

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

the length of the oval track is equal to sum of two lengths of the rectangle (each ) and circumference of the circle (you got two semicircles on each end)

assuming that the semicircle is on the end then: radius will be
and the length will be:

=>ans. for the length
the area enclosed by the track will be equal to the area of rectangle plus the area of circle:

...=> ans. for the area

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