SOLUTION: Given: ΔABC, AB = BC = AC= a. Find: The area of ΔABC
Algebra.Com
Question 1104721: Given: ΔABC, AB = BC = AC= a. Find: The area of ΔABC
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
It's an equilateral triangle with sides = a
-----------
base b = a
Height h = sqrt(a^2 - (a/2)^2) = a*sqrt(3)/2
============
For any regular polygon with n sides = s:
Area = ns^2*cot(180/n)/4
= 3a^2*cot(60)/4
= a^2*sqrt(3)/4 ---- same answer
RELATED QUESTIONS
In ΔABC ,D is the midpoint of BC. If Δ ABD~ΔACD, then prove that AB=AC.
(answered by ikleyn)
How do I find the height of a triangle if I am only given the length of 2 sides?... (answered by solver91311)
ΔABC has a perimeter of 30. AB = 4x – 7, BC = 2x, and AC = 7. List the angles in... (answered by solver91311)
ΔABC and ΔXYZ are similar triangles. If BC = x + 5, AC = x + 1, YZ = x + 3, and (answered by fractalier)
Given: RT Δ ABC, with RT, ∢ at C , DC ⊥ AB
AC= √2 and, BC =... (answered by MRperkins)
In the ΔABC, AB = 16 in, BC = 9 in, AC = 10 in. AD ⊥ to the extended BC. Find... (answered by greenestamps)
In ΔABC, AC = BC, CD ⊥ AB with D ∈ AB , AB = 4 in, and CD = √3... (answered by Theo)
In ΔABC, AB = 10 and BC = 5. Which expression is always true?
A. AC = 5
B.... (answered by solver91311)
The perpendicular bisectors of sides
AC
and
BC
of ΔABC intersect side
AB
(answered by MathLover1)