SOLUTION: ABCD is a kite AD 6.4 CM DC 9.7 CM ANGLE ADC = 110 DEGREES WORK OUT THE AREA THANK YOU

Algebra.Com
Question 1099459: ABCD is a kite
AD 6.4 CM
DC 9.7 CM
ANGLE ADC = 110 DEGREES
WORK OUT THE AREA
THANK YOU

Answer by Edwin McCravy(20065)   (Show Source): You can put this solution on YOUR website!







To find the area of triangle ADC, we can use the formula:

"The area of a triangle is one-half the product of two
sides multiplied by the sine of the angle between those
two sides."

So,



Calculate that with what you're given and then multiply what
you get by 2 since the area of the kite is twice the area of 
triangle ADC.

Edwin


RELATED QUESTIONS

The parallel sides of trapezoid ABCD are 3 cm and 9 cm(AB and DC).The non parallel sides... (answered by Edwin McCravy)
In the diagram below, ABCD is a parallelogram with AB=42 cm. Arc AD is a semi-circle. The (answered by greenestamps)
ABC is a triangle ADC is a straight line with BD perpendicular to AC AB = 7 cm BC =... (answered by rothauserc)
Given ABCD is a trapezoid with BC parallel to AD. If AB = AD = 4, angle A = 60 degrees,... (answered by Edwin McCravy,AnlytcPhil,math_tutor2020)
the diagram shows a solid prism of lenght 15 cm. the section of the prism is the... (answered by ikleyn)
how do you find the measure of angle ABC if the measure of angle ADC=112 degrees. The... (answered by solver91311)
If AD=(x+6)cm, AB=5cm and the perimeter of ABCD is 26cm, find the area of rectangle... (answered by checkley77)
In the diagram, ABCD is a parallelogram with AB=37 cm. AD is a semi- circle. The area... (answered by ikleyn)
In the figure below, ADC is a chord of a circle centre O and passing through the points... (answered by ikleyn,Edwin McCravy)