SOLUTION: the width of a rectangle is x centimetres the length of a diagonal of the rectangel is 12 cm. the perimeter of the rectangle is 28cm. fine the value of x . give your values correc

Question 1075802: the width of a rectangle is x centimetres the length of a diagonal of the rectangel is 12 cm. the perimeter of the rectangle is 28cm. fine the value of x . give your values correct to 3 significant figures.
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Found 2 solutions by josgarithmetic, jorel1380:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Length is from Pythagorean Theorem formula.

If L is length,

Find L^2.

.

Equate the two expressions of L^2.

you can finish from here.
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
If the width is x, then 2x+2*length=28
2*length=28-2x
length=14-x
So:
x�+(14-x)�=12�=144
x�+x�-28x+196-144=0
2x�-28x+52=0
x�-14x+26=0
x�-14x+49=49-26
(x-7)�=23
x-7=+/-√23
x=7+/-√23=11.796 or 2.204 ☺☺☺☺

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