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The square poster has sides measuring 2 feet less than the sides of a square sign. If the distance between their area is 52 square feet
find the lengths of the sides of the poster and the sign.
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Answer. 12 cm (poster) and 14 cm (sign).
x - y = 2, (1)
x^2 - y^2 = 52. (2)
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x - y = 2, (1')
(X+y)*(x-y) = 52. (2')
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x - y = 2, (1'')
x + y = 26. (2'')
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add (1'') and (2'') to get x = 14.
Then y = 14 - 2 = 12.
Solved.