SOLUTION: The equations y = 2x - 1 and y = -1/2x + 4 intersect in Quadrant I. Find the area of the triangle formed with this point of intersection and the two y-intercepts of the lines.

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Question 1050683: The equations y = 2x - 1 and y = -1/2x + 4 intersect in Quadrant I. Find the area of the triangle formed with this point of intersection and the two y-intercepts of the lines.
Found 3 solutions by ewatrrr, Fombitz, josmiceli:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

A = (1/2)bh
A = (1/2)5*2 = 5 units^2

Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Graphically,
.
.
.
.
.
.
.
The y intercepts are -1 and 4 respectively so the base of the triangle is
The height of the triangle is .
You can also find this using the intersection point of the two lines by setting them equal to each other,




So,


Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Find the point of intersection


---------------------
By substitution:

Multiply both sides by



and



----------------------------
The intersection is at ( 2,3 )
----------------------------
Now find the y-intercepts
by setting
-----------------------------



( 0, -1 )
----------------



( 0, 4 }
--------------------
The distance between the 2 y-intercepts is:


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The height of the triangle formed is
the x-value of the intersection ( 2,3 )
which is
---------------------


The area is 5 square units
------------------------
Here's the plot of the lines:




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