SOLUTION: A right triangle has one vertex on the graph of y=x^5 , x>0, at (x,y) another at the origin, and a third on the positive y-axis at (0,y). Express the area A of the triangle as a fu

Question 1048269: A right triangle has one vertex on the graph of y=x^5 , x>0, at (x,y) another at the origin, and a third on the positive y-axis at (0,y). Express the area A of the triangle as a function of x
Found 2 solutions by MathLover1, advanced_Learner:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
A right triangle has one vertex on the graph of , , at (,)
another at the origin, or (,)
and a third on the positive y-axis at (,)
remember, we let ; so, replace "" with to get (,)

let's draw a picture:

since the point (,) is "" units to the and "" units , this means that the of the triangle is "" units long and the is "" units

So the base is "" and the height is
Now recall (or look up), the area of any triangle is

..........substitute and

Answer by advanced_Learner(501) (Show Source): You can put this solution on YOUR website!
1/2*x^6
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