SOLUTION: How would I set up to figure the area of 560 sq ft with a length of 12 greater than the width's dimension. What are the dimensions?

SOLUTION: How would I set up to figure the area of 560 sq ft with a length of 12 greater than the width's dimension. What are the dimensions?

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Question 104616: How would I set up to figure the area of 560 sq ft with a length of 12 greater than the width's dimension. What are the dimensions?
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
let x=width, so x+12=length ... x(x+12)=560 ... x^2+12x=560

x^2+12x-560=0
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