SOLUTION: The breadths of two rectangles ,P and Q ,have 14cm and 8 cm.the sum of the lenghts of P and Q is 22cm, and the sum of their areas is 236 cm suared .what is the area of P?

Question 1009801: The breadths of two rectangles ,P and Q ,have 14cm and 8 cm.the sum of the lenghts of P and Q is 22cm, and the sum of their areas is 236 cm suared .what is the area of P?
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
X=length of P; 22cm-X=length of Q
.
(14cm)(X)+(8cm)(22cm-X)=236cm^2
14Xcm+176cm^2-8Xcm=236cm^2
6Xcm=60cm^2
X=10cm
.
Area of P=(14cm)(10cm)=140cm^2
.
CHECK:
Length of Q=22cm-10cm=12cm
Area of Q=(8cm)(12cm)=96cm^2
.
(Area of P)+(Area of Q)=236cm^2
(140cm^2)+(96cm^2)=236cm^2
236cm^2=236cm^2
RELATED QUESTIONS
Two angles are complementary if the sum of their measures is 90�. (answered by Alan3354)
Two numbers p and q have a sum of 27 Two numbers p and q have a sum of 27. Find the... (answered by Cromlix)
A pair of dice is rolled. Let P denote the event �the sum shown is 8� and Q the event... (answered by robertb)
P and Q represent numbers, and P * Q means (P+Q)/2. What is the value of... (answered by ikleyn)
the sum of p and q is twice their difference what is the ratio of p to q ?please include... (answered by stanbon)
If p and q are consecutive negative even integers whose sum is -120, and q < p, what is... (answered by edjones)
if p and q are consecutive even integers whose sum is -120, and q (answered by ikleyn)
The positive integers p,q. p-q and p+q are all prime numbers. The sum of all these... (answered by richard1234)
If P and Q are two positive number,p+q=480 and p is 40 greater than q,then find the value (answered by rothauserc)