SOLUTION: A landscape architect is planning a new nature area in middle of campus. She wants the length to be twice the width, and wants to put a 3foot high retaining wall around the perimet

Question 1000584: A landscape architect is planning a new nature area in middle of campus. She wants the length to be twice the width, and wants to put a 3foot high retaining wall around the perimeter. There will be 300 total feet wall installed. How wide will this area be?
I think it's α=l*w
But now I'm lost, could someone help me?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39626) (Show Source): You can put this solution on YOUR website!
Perimeter may match the 300 total feet retaining wall.
w width, L length;
L=2w

and since the question is to find w, just substitute for L.

Answer by MathTherapy(10556) (Show Source): You can put this solution on YOUR website!

A landscape architect is planning a new nature area in middle of campus. She wants the length to be twice the width, and wants to put a 3foot high retaining wall around the perimeter. There will be 300 total feet wall installed. How wide will this area be?
I think it's α=l*w
But now I'm lost, could someone help me?

Width of nature area: ft
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