SOLUTION: A six-sided die has been tossed 4 times. How many sequences of these 4 outcomes contain at least one number greater than 4?

Algebra.Com
Question 1167302: A six-sided die has been tossed 4 times. How many sequences of these 4 outcomes contain at least one number greater than 4?
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
Since the die has 6 faces, there are (6)(6)(6)(6) = 64 = 1296 possible
sequences.

From these 1296 sequences we must eliminate all sequences which fail. These are
all the ways in which all 4 rolls are 1,2,3, or 4.  There are (4)(4)(4)(4) =
44 = 256 sequences which fail.

So 1296-256 = 1040 sequences contain at least one number greater than 4? 

Answer = 1040

Edwin

RELATED QUESTIONS

a single six-sided fair die is tossed. Find the probability of obtaining a number greater (answered by ikleyn)
Justin throws a standard six-sided die three times in a row and notes the number of dots... (answered by ikleyn)
A standard six-sided die is rolled $7$ times. You are told that among the rolls, there... (answered by ikleyn)
An ordinary die is tossed four times. What is the probability of obtaining a number... (answered by richard1234)
A standard six-sided die is rolled $8$ times. You are told that among the rolls, there... (answered by ikleyn)
The outcome of chance events in a fantasy role-playing game is determined by rolling... (answered by ikleyn)
A quarter is tossed 7 times How many different sequences of outcomes are... (answered by ikleyn,saw)
which pair of events are complementary events? - rolling a 4 or greater with a 6 sided... (answered by stanbon)
A pair of 6 sided dice are tossed. What is the probability that at least one of the dice... (answered by math_tutor2020,ikleyn)