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Tutors Answer Your Questions about Square-cubic-other-roots (FREE)
Question 74659: Evaluate: , if possible
My answer was 24, but the answers given was:
a)-4
b)-8
c)-64/3
d) Not a real number
Is there something I am doing wrong, or is there another way of doing this problem to get one of these answers? Thanks
Click here to see answer by funmath(2925) |
Question 75646: Back in the good old days, they taught us a 'long hand' method for solving Square, Cube, and Nth roots of any number. For instance square root of 139, or 6th root of 13. I have since forgotten (after 35years) how to do that and want to teach my son, rather than the current approach of memorizing your perfect squares, cubes, etc. Those formulas exist and are embedded in modern scientific calculators, but I am unable to find them in any textbook, online, etc.
Please remind me how to do this.
Thanks
Click here to see answer by Edwin McCravy(8893)  |
Question 78453: hsving trouble understanding N-th root. Can you explain what it is, and how to solve problems with them. I have muddled thru square root ok, but having a little problem with cubic root, and don't know anything at all about N-th root.
Any help will be greatly appreciated. By the way, I am a 72 year old lady trying to learn Algebra. So far, so good. Thanks. Mary
Click here to see answer by stanbon(57282) |
Question 78697: Please help me solve the following problem for c.
550,000 = {1} Divided by {2pie}Times the square root of {.000000000010 Times c}
The text provideds the answer but does not explain how to slove it.
Any help would be greatly appreciated.
Thanks,
Michael H.
Click here to see answer by mathdoc314(58) |
Question 79475: I am stuck on my last question. the word problem is "a store has 360 square meters of floor space. The length of the store is 9 meters greater than its width. Find the length and width." I started to resolve this by w(w+9)= 360. Then I put it into an equation which is w^2 + 6w = 360, then I made the equation = zero by subtracting 360 and moving it to the left side of the equation. Now I am stuck.
thanks,
Michael
Click here to see answer by stanbon(57282) |
Question 79542: I suspect that the second statement is false. Can you please explain where I'm going wrong?
3/(square(2,5)) = 3/(5^1/2) = 3(5^-1/2)
3/(square(2,5)) = 3/(square(2,5)) * [(square(2,5))/(square(2,5))] = 3(square(2,5))/5 = 3(5^1/2)/5
Click here to see answer by Earlsdon(6287) |
Question 79542: I suspect that the second statement is false. Can you please explain where I'm going wrong?
3/(square(2,5)) = 3/(5^1/2) = 3(5^-1/2)
3/(square(2,5)) = 3/(square(2,5)) * [(square(2,5))/(square(2,5))] = 3(square(2,5))/5 = 3(5^1/2)/5
Click here to see answer by stanbon(57282) |
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