|
Tutors Answer Your Questions about Square-cubic-other-roots (FREE)
Question 101536: Please help me with this problem? A virus takes up a volume of approximately 8.5x10-14 cubic centimeters. Calculate the estimated number of viruses in 28 cubic centimeters.
I tried to solve by o.ooooooooooooo85x28...and was not successful. Thank you
Click here to see answer by Fombitz(13828)   |
Question 101827: Use a calculator to find the approximate decimal value of the follow rational and irrational numbers. Round to the nearest tenth.
-2(to the square root of)5
and
(cubed root of)-15
[Sorry if that doesn't make sense but I don't know how to make a square root symbol]
I thought that these didn't have answers because you can't have negative square roots?
Click here to see answer by Fombitz(13828) |
Question 101826: I need To find what the square root of
1,987,654
it is an extra credit problem i need to answer by friday i have an F in the class and this will make it an A please help
THE QUESTION IS IN NO TEXTBOOK
Click here to see answer by bucky(2189) |
Question 102399: Good Evening Tutor,
I need to check my answers for these two problems could you tell me if I have them correct?
1. Simplify 2 sqrt of 12 + 4 sqrt of 27
I have 2 sqrt of 39 (correct?)
2.) Simplify 6 sqrt of 2 - 6 sqrt of 7
is this 6 sqrt of 5?
Thank you for your help.
Click here to see answer by stanbon(57984) |
Question 101671: Tutor,
Could you please check my answer and let me know if I have this answer correct?
Find length x in each triangle. Express your answer in simplified radical form.
longest side is 12, next side is x and botton and smallest side is 8
I got x = sqrt of 80
That seems off to me I am not sure I solved this correctly so I would appreciate your help.
Thank you very much for your help.
Click here to see answer by Fombitz(13828) |
Question 103300: I have two problems. I worked part of one but cannot get it finished and don't know why. It is
-16t^2 + 112t = 120
-16t^2 + 112t - 120 = 0
t=(-112±√(〖112〗^2-4∙(-16)∙(-120) ))/(2∙(-16) )
t=(-112±√(12544-7680))/(-32)
t= (-112±√4864)/(-32)
And the other is Find the distance between (–4, 0) and (–5, –3)I put...
-5+(-4)=-9
-3+0=-3
-9^2+-3^2=h^2
81+9=h^2
h=sqrt90
h=sqrt9*10
h=3sqrt10
Where did I go wrong????
Click here to see answer by stanbon(57984) |
Question 103816: I hope I am in the right topic area. I need to figure out this problem and it has to be solved using the square root property. Can someone please help?
2x^2 - 35 = 15
further directions from my Professor are as follows:
Make sure that your work is demonstrating the solving method given in the instructions. Use the Insert and Symbols menus in Word to present the radical √ and plus/minus ± symbols. Remember that radicands must be enclosed within [ ]. Typing your work vertically is preferred but optional. If you choose to type horizontally, make sure you are appropriately using grouping symbols.
Thank You very Much!
Click here to see answer by ankor@dixie-net.com(15747)  |
Question 103818: I need to figure out this problem and it has to be solved using the square root property. Can someone please help?
(x + 6)^2 = 4
further directions from my Professor are as follows:
Make sure that your work is demonstrating the solving method given in the instructions. Use the Insert and Symbols menus in Word to present the radical √ and plus/minus ± symbols. Remember that radicands must be enclosed within [ ]. Typing your work vertically is preferred but optional. If you choose to type horizontally, make sure you are appropriately using grouping symbols.
Thank You very Much!
Click here to see answer by jim_thompson5910(28717) |
Question 103991: I need to know how to solve a problem. I no the answer but i dont no how to expain. the prolem shows a tiny 3 almost ontop of the square root symbol then the square root -243 which i have to simlify. the answer is -6 but i dont no how to explain how i got my answer! please help me!!!!!
Click here to see answer by jim_thompson5910(28717) |
Question 104663: x-2*sqrt(x-3)=3
solve for zero...
I subtract x from both sides which =
-2*sqrt(x-3)=3-x
then I divide by -2 from both sides
sqrt(x-3)=(3-x)/-2
then to get rid of the "sqrt" ^2 on both sides
x-3=(9+x^2)/4
then I subtract "x" and add 3 to both sides to solve for zero.
0=(9+x^2)/4-x+3
then I find a common denominator of 4 and solve
0=(9+x^2)/4 -4x/4+12/4 which equals 0=(x^2-4x+21)/4
then I multiply 4/1 on both side the loose the denominator.
0=x^2-4x+21 which can not be factored, but my text book gives a solution set of {7,3}. I cant find were I went wrong, please help
Click here to see answer by stanbon(57984) |
Question 104710: x-2*sqrt(x-3)=3
solve for zero...
I subtract x from both sides which =
-2*sqrt(x-3)=3-x
then I divide by -2 from both sides
sqrt(x-3)=(3-x)/-2
then to get rid of the "sqrt" ^2 on both sides
x-3=(9+x^2)/4
then I subtract "x" and add 3 to both sides to solve for zero.
0=(9+x^2)/4-x+3
then I find a common denominator of 4 and solve
0=(9+x^2)/4 -4x/4+12/4 which equals 0=(x^2-4x+21)/4
then I multiply 4/1 on both side the loose the denominator.
0=x^2-4x+21 which can not be factored, but my text book gives a solution set of {7,3}. I cant find were I went wrong, please help.
Please note, this question had already been answered but the link to the answer did not work so this is why I am re-submitting it. Thank you.
Click here to see answer by Fombitz(13828) |
Question 104710: x-2*sqrt(x-3)=3
solve for zero...
I subtract x from both sides which =
-2*sqrt(x-3)=3-x
then I divide by -2 from both sides
sqrt(x-3)=(3-x)/-2
then to get rid of the "sqrt" ^2 on both sides
x-3=(9+x^2)/4
then I subtract "x" and add 3 to both sides to solve for zero.
0=(9+x^2)/4-x+3
then I find a common denominator of 4 and solve
0=(9+x^2)/4 -4x/4+12/4 which equals 0=(x^2-4x+21)/4
then I multiply 4/1 on both side the loose the denominator.
0=x^2-4x+21 which can not be factored, but my text book gives a solution set of {7,3}. I cant find were I went wrong, please help.
Please note, this question had already been answered but the link to the answer did not work so this is why I am re-submitting it. Thank you.
Click here to see answer by jim_thompson5910(28717) |
Question 105649: general right angle trig: if cos(theta) = 2/5, find the value of tan(theta)
i did pythagoren theroy
a^2 + b^2 = c^2
2^2 + b^2 = 5^2
4 + b^2 = 25
b^2 = square root of 21
how do you simplify the square root of 21? like what is it simplified?
Click here to see answer by edjones(7569)  |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490
|
| |
