SOLUTION: 2ps2= 3qs2 + 5p make s the subject of the formulae The 2nd and third "2" are exponents

Algebra.Com
Question 985798: 2ps2= 3qs2 + 5p make s the subject of the formulae
The 2nd and third "2" are exponents

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
2ps^2= 3qs^2 + 5p make s the subject of the formula
2ps^2 - 3qs^2 = 5p
s^2*(2p - 3q) = 5p
s^2 = 5p/(2p - 3q)

Or,


RELATED QUESTIONS

X/y = sqrt[v2 /U2] make v the subject of the formulae. The "2" are exponents, please... (answered by josgarithmetic)
T^2= sqrt(m+2/m-5) make m the subject of the formulae (answered by solver91311)
3sqrt(2x2 - 7) = y/z make x the subject of the formulae The second 2 is an... (answered by MathLover1)
p/q=1/3(sqrt[h+2k/3h+k] make h the subject of the... (answered by MathLover1)
Log a^x =p+q. Make x the subject of the formulae (answered by Alan3354)
X/y = sqrt[v2/U2] make v the subject of the... (answered by josgarithmetic)
a+x/a-x = b-y/b+y make x the subject of the... (answered by josgarithmetic,MathTherapy)
Y= nx/a(4x-3) make x the subject of the formulae (answered by Alan3354)