SOLUTION: Please check to see if I am doing this the correct way. SOLVE AND CHECK ~(4x+4)+12=0 ~(4x+4)=-12 (~(4x+4))^(2)=(-12)^(2) (~(4(x+1)))^(2)=(-12)^(2) (2)^(2)=(-12)^(2

Question 98223: Please check to see if I am doing this the correct way.
SOLVE AND CHECK
~(4x+4)+12=0
~(4x+4)=-12
(~(4x+4))^(2)=(-12)^(2)
(~(4(x+1)))^(2)=(-12)^(2)
(2)^(2)=(-12)^(2)
(2~(x+1))^(2)=(-12)^(2)
4(x+1)=(-12)^(2)
(4x+4)=(-12)^(2)
4x+4=(-12)^(2)
4x+4=(144)
4x+4=144
4x=140
x=35
No Solution
Thank you
Found 2 solutions by benni1013, mathslover:
Answer by benni1013(206) (Show Source): You can put this solution on YOUR website!
Hold on and back the heck up: Here is how you do this problem.
(4x+4)+12=0
(4x+4)=-12. You right up to this point now pay attention
4(x+1)=-12. See what I did I made a GCF out the quantity inside the parentheses.
x+1=-3
x=-4
Answer by mathslover(157) (Show Source): You can put this solution on YOUR website!
i am assuming that you meant the question to be

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