SOLUTION: Hi!
What is the simplified answer for this
The index of both square rt is 5
Sqrt( x^4y^6) x sqrt(x^6y^12)
And please do explain how
Thank you very much :)
Algebra.Com
Question 980803: Hi!
What is the simplified answer for this
The index of both square rt is 5
Sqrt( x^4y^6) x sqrt(x^6y^12)
And please do explain how
Thank you very much :)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
What is the simplified answer for this
The index of both square rt is 5
Sqrt( x^4y^6) x sqrt(x^6y^12)
=======================
It's not a square root with an index.
It's a 5th root.
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5throot( x^4y^6) x 5throot(x^6y^12)
Don't use x for multiply, use * (Shift 8)
x is used for other things.
The indices are the same, 5, so multiply
=
Add exponents when multiplying
=
=
=
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Solve for x.
x^4 - 5x^2 -12 = 0
I can write x^4 like this: (x^2)^2.
Let u = x^2.
(answered by ikleyn,greenestamps)