SOLUTION: The length a rectangle is twice that of its width. If the area of the rectangle is 72 square inches, then find the length and width. How do I do this please include details and e

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Question 939757: The length a rectangle is twice that of its width. If the area of the rectangle is 72 square inches, then find the length and width.
How do I do this please include details and each step thank you
Someone else answered the question with the answer as w=6
L=12. But I don't understand how they got it if someone can give me the steps or explain it to me please.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
The very same example problem has been asked and answered a few times already.

w for width, L for length;
Given is L=2w, and using A for area, A=72.

Formula for area using the assigned variables, wL=A.

Summarizing the list of equations, purely in symbols:
L=2w
wL=A
-
KNOWN: A=72
UNKNOWN: w and L

Solution Process:







Your choice if you want to rationalize the denominator, but knowing that will be a whole number here, rationalizing does not matter much.

means now .

Plug-in the given value and evaluate w and L.

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The length a rectangle is twice that of its width. If the area of the rectangle is 72 square inches, then find the length and width.
How do I do this please include details and each step thank you
Someone else answered the question with the answer as w=6
L=12. But I don't understand how they got it if someone can give me the steps or explain it to me please.

Let width be W
Then length = 2W
Area = LW, and since area = 72 sq in, we get:
2W(W) = 72



W, or width = , or inches
Length: 2(6), or inches
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