SOLUTION: I am having trouble solving this problem. sqrt(x+2)(x-6)=x-5.....the (x+2) and (x-6) are both under the same square root.
Algebra.Com
Question 927348: I am having trouble solving this problem. sqrt(x+2)(x-6)=x-5.....the (x+2) and (x-6) are both under the same square root.
Answer by srinivas.g(540) (Show Source): You can put this solution on YOUR website!
squaring on both sides
move x^2-10x+25 to the right
move -37 to the right
divide with 6 on both sides
RELATED QUESTIONS
Hi,I am having trouble with this problem,{{{x-5}}}/{{{x^2-7x+10}}}x{{{x^2+x-6}}}/{{{5}}}
(answered by Edwin McCravy)
Solve the equation. Show your work.
the following are under one square root symbol:... (answered by jsmallt9)
I am having trouble solving this problem because of all the negatives. Could someone... (answered by Earlsdon)
I am having trouble solving a system of equations:
{{{4sqrt(x^2-3x) - 3sqrt(y^2+6y)=... (answered by ankor@dixie-net.com)
I am having trouble and are looking for your assistance. I am subtracting rational... (answered by josgarithmetic,MathTherapy)
I am having a problem solving this problem:
Is the square root of x^2 =x an identity... (answered by THANApHD)
How do you solve 0= sqrt x+5? the x+5 are both under the same square-root. I just... (answered by Fombitz)
I am having trouble solving this eqation... x/6 + 3x/4 +1 =2x/3 +... (answered by stanbon)
I am having trouble getting the correct answer to this problem. The problem is
1/x+3 = (answered by unlockmath,mananth)