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Square both sides of the equation:

Put the equation in standard form:

Factor:

Equate each factor to 0 and solve for x:

Now, you need to plug these results back into the original equation to see if it still holds true. You can see that x=2 is a valid answer, since the equation holds when you plug that one in. However, x=-1 does not hold true. That is called an "extraneous root." It's a result of solving the problem, but it is not a valid answer. The only correct answer is:

Good Luck,
tutor_paul@yahoo.com