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10x^2=4x+7 ... 10x^2-4x-7=0
completing the square - step-by-step ... for ax^2+bx+c=0
1) by dividing or multiplying, set the coefficient of the squared term equal to one ... x^2+(b/a)x+(c/a)=0
2) by adding or subtracting, set the constant term (c/a) equal to zero ... x^2+(b/a)x=-(c/a)
3) add the square of one half of the x coefficient to both sides ... x^2+(b/a)x+(b/(2a))^2=-(c/a)+(b/(2a))^2
4) take the square root of both sides ...
, realizing the root is positive AND negative
x-(1/5)=
... (c) is the answer
