SOLUTION: Hello, I cannot find topic - Factoring a Perfect-Square Trinomial My problem is: 16x^2 - 40x + 25 - Okay I know that the first & third #'s need to squared. But I'm g

Algebra.Com
Question 90921This question is from textbook Elementary Algebra
: Hello,
I cannot find topic - Factoring a Perfect-Square Trinomial
My problem is:
16x^2 - 40x + 25 - Okay I know that the first & third #'s need to squared.
But I'm getting lost trying to break it down.....the examples gives:
(4x)^2 - 2(4x)(5)+ 5^2 = (4x-5)^2
I just can't seem to figure out how they got there.
Thanks for any help you can give...hope it makes sense...
Cristina
This question is from textbook Elementary Algebra

Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!
you can build a perfect square trinomial from scratch ... (m+n)^2 ... FOILing gives m^2+mn+mn+n^2 or m^2+2mn+n^2

in your problem, m is 4x and n is -5 ... (4x-5)^2=(4x)^2+4x(-5)+4x(-5)+(-5)^2=16x^2-20x-20x+25=16x^2-40x+25

the example doesn't have the minus sign associated with the 5, which could be causing confusion

RELATED QUESTIONS

Complete the trinomial so it is a perfect square. 16x^2 + ___+... (answered by jim_thompson5910)
Find the value of "c" that makes the trinomial a perfect square:... (answered by ilana)
Hello out there,I may be in the wrong place for these problems but I didn't see any other (answered by stanbon)
How do I factor 25y^2 - 10y + 1? I thought it was a perfect square trinomial, but... (answered by Alan3354,aquyu214,MathTherapy)
Hello, I'm having trouble solving the second part of this equation. Its a factoring... (answered by colliefan)
Okay my algebra teacher is teaching us polynomials to a factor, the difference of two... (answered by jim_thompson5910)
Find the value of "n" such that x^2-17x+n is a perfect square trinomial. I need help with (answered by Fombitz)
How do I find the value of an equation that is a perfect square trinomial? (answered by mhel12jhane)
Simplify by factoring the square root of 1575x^4 (x is to the 4th power). I don't know... (answered by jim_thompson5910)