SOLUTION: Can you help me with this problem.
Find the solution sets for
(sqrt2x+1) - (sqrt x) = 1
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Question 89345: Can you help me with this problem.
Find the solution sets for
(sqrt2x+1) - (sqrt x) = 1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(sqrt2x+1) - (sqrt x) = 1
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Square both sides to get:
2x+1 -2sqrt(x(2x+1)) + x = 1
Simplify and isolate the remaining radical, as follows:
2sqrt(2x^2+x) =3x
Square both sides to get:
4(2x^2+x) = 9x^2
8x^2+4x = 9x^2
x^2-4x=0
x(x-4)=0
x=0 or x=4
Check the answer in the original equation:(sqrt2x+1) - (sqrt x) = 1
Does x=0? : sqrt(1)-sqrt(1)=1 : False
Does x=4? ; sqrt(9)-sqrt(4) = 1 : True
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Final Answer: x=4
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Cheers,
Stan H.
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