SOLUTION: solve using substitution 0.1x+0.8y=23 0.7x-0.5y=83

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Question 884445: solve using substitution 0.1x+0.8y=23
0.7x-0.5y=83
Found 2 solutions by Fombitz, MathTherapy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Multiply both equations by 10.
x%2B8y=23
7x-5y=83
From eq. 1,
x=23-8y
Substitute into eq. 2,
7%2823-8y%29-5y=83
161-56y-5y=83
-61y=-78
y=78%2F61
Then,
x=23%2B8%2878%2F61%29
x=1403%2F61-624%2F61
x=779%2F61

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

solve using substitution 0.1x+0.8y=23
0.7x-0.5y=83


highlight_green%28highlight_green%28x+=+78%2F6.1%29%29

highlight_green%28highlight_green%28y+=+7790%2F61%29%29

You can do the check!! 



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