SOLUTION: Solve the question by completing the square. 4x^2-5x+1=0. I keep messing the answer up. The answer should be x=1 and x=1/4

Question 861281: Solve the question by completing the square. 4x^2-5x+1=0. I keep messing the answer up. The answer should be x=1 and x=1/4
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
by factoring
4x^2-5x+1=0
(4x-1)*(x-1)
complete the square
4x^2-5x+1=0
x^2-5/4x=-1/4
take half of 5/4 and square it
5/8^2= 25/64
x^2-5/4x+25/64=-16/64+25/64
(x-5/8)^2=9/64

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=9 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 1, 0.25. Here's your graph:

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