SOLUTION: Simplify and ractionalize all denominators: 3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)] I really dont know where to start with this question, I would like to see all the steps and the

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Question 83550: Simplify and ractionalize all denominators:
3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
I really dont know where to start with this question, I would like to see all the steps and the answer so i can break it down and understand each step. Thank you in advance!

Found 2 solutions by stanbon, Edwin McCravy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
Simplify the SQRT factors to get:
= 3b[3a^2(sqrt3ab)] + 2a[a^2b^2(sqrt3ab)]
Factor out the common factor of sqrt3ab to get:
= [9a^2 + 2a^3b^2][sqrt3ab]
Cheers,
Stan H.

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!

Stanbon's solution to your problem is incorrect.

Simplify and ractionalize all denominators:

 

There are no denominators to rationalize, so we just simplify this one

Break up what's under the radicals completely into prime factors:

Break up  into primes as 

Break up  into primes 

Substitute these under the radicals:

 + 

Since the index of the root is 2 (square root) we group all
like factors by twos (pairs) that we can like this.  We will
often have factors left over that would not pair up:

 + 

Each pair of like factors can be written as a square

 + 

Take out each square from under the radical out front of the radical,
like this, leaving what didn't pair up under the radical:

 + 

Simplify what's in front of the radicals:

 + 

Now you can factor out GCF = 

( + )





Edwin


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