SOLUTION: Find the half-life of a radioactive element that decays according to the rule: dA/dt=-0.014A where A is the amount in kg present after t years.

Question 80212: Find the half-life of a radioactive element that decays according to the rule:
dA/dt=-0.014A
where A is the amount in kg present after t years.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the half-life of a radioactive element that decays according to the rule:
dA/dt=-0.014A
where A is the amount in kg present after t years.
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Integrating you get A(t)=-0.014At
If A is doubled you have:
2A=-0.014At
2=-0.014t
t=2/-0.014
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Comment:
This would give you a negative value for t.
I think something is missing in your posting.
Decay functions are exponential. Your posting
does not lead to that conclusion.
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Cheers,
Stan H.
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