SOLUTION: explain why the square root of -25 has no real solutions.

SOLUTION: explain why the square root of -25 has no real solutions.

Algebra.Com

Question 774377: explain why the square root of -25 has no real solutions.

Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
by definition if b^2=a then b is the root of a. Since there is no real number for which b^2 < 0, there is no real number for which b^2 = -25
RELATED QUESTIONS
Explain why the equation x^2 = 4 has two real number solutions, while the equation the... (answered by stanbon)

Explain why x to the 4th+2xsquared+4 has no real root while every polynomial function of... (answered by Fermat,venugopalramana)

Explain why the square root of 25 belongs to 4 subsets of the real numbers , but the... (answered by Edwin McCravy)

Explain why (square root of -64) is not a real number and why (square root of 3,-64) is a (answered by stanbon)

Explain why the equation |x| > -1/2 has all real number solutions. (answered by ikleyn,math_tutor2020)

solve the eqaution. If the equation has no real solution, so state. square root of k... (answered by rapaljer)

solve the eqaution. If the equation has no real solution, so state. square root of q +... (answered by solver91311)

solve the eqaution. If the equation has no real solution, so state. square root of q... (answered by Earlsdon,jsmallt9)

solve the eqaution. If the equation has no real solution, so state. (the q + 4 is under (answered by richwmiller)