SOLUTION: Sn=n/2(2a +(n-1)d)
a=2 and d=2
Algebra.Com
Question 755216: Sn=n/2(2a +(n-1)d)
a=2 and d=2
Answer by dkppathak(439) (Show Source): You can put this solution on YOUR website!
Sn=n/2(2a +(n-1)d) WHERE a=2 d=2
Sn=n/2(2x2 +(n-1)2)
=n/2(4+2n-2)
=n/2(2n+2)
n/2x2(n+1)
n(n+1)answer
RELATED QUESTIONS
Sn=n/2(2a +(n-1)d)
a=2 and... (answered by tommyt3rd)
please help me to make n the subject of the formula in: Sn=... (answered by josgarithmetic)
S=n/2(2a(n-1)d) (answered by mananth,ikleyn)
{sn}={n^2-n} (answered by Edwin McCravy,Alan3354)
Solve for a: s=n/2... (answered by lynnlo)
find the sum when N=20 ,A=2 and D=5 for... (answered by ewatrrr)
If s=n/2(2a+(n-1)d)express d in terms of a,n and S
(answered by ikleyn)
Please solve:
Sn=a^2+(a+d)^2+(a+2d)^2+(a+3d)^2+....+[(a+(n-1)d]^2... (answered by ikleyn)
Let Sn = 1+2+4+...+2^n-1. Find {n: Sn > 1 000... (answered by greenestamps)