# SOLUTION: simplify 6 - 7 times the square root of 3 DIVIDED BY 2 times the square root of 3 + 4

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 Click here to see ALL problems on Square-cubic-other-roots Question 66033This question is from textbook an incremental development : simplify 6 - 7 times the square root of 3 DIVIDED BY 2 times the square root of 3 + 4This question is from textbook an incremental development Answer by ptaylor(2048)   (Show Source): You can put this solution on YOUR website!simplify 6 - 7 times the square root of 3 DIVIDED BY 2 times the square root of 3 + 4 (6-7sqrt3)/(4+2sqrt3) First, multiply both numerator and denominator by(4-2sqrt3), the conjugate of (4+2sqrt3). This will get rid of the radical in the denominator. NUMERATOR: (6-7sqrt3)(4-2sqrt3)=24-28sqrt3-12sqrt3+(14)(3)=66-40sqrt3 DENOMINATOR(4+2sqrt3)/(4-2sqrt3)=16+8sqrt3-8sqrt3-(4)(3)=16-12=4 Now we have (66-40sqrt3)/4 divide numerator and denominator by 2 and we get: (33-20sqrt3)/2 Hope this helps----ptaylor