SOLUTION: Please, Please, Please can someone help me to solve this equation. I am so confused. Thank you for your quick response!
W = 33 – (10.45 + 10√(v-v) ) (33-T)
a. T = 10
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Question 596126: Please, Please, Please can someone help me to solve this equation. I am so confused. Thank you for your quick response!
W = 33 – (10.45 + 10√(v-v) ) (33-T)
a. T = 10c; v = 9m/sec
b. T= 0c; v = 15m/sec
c. T=-10c, v=20/sec
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
(I would encourage you to not use the "check mark" symbol in the future. On algebra.com use "sqrt(...)" for square roots. :sqrt" is not standard notation in Math but think every tutor on algebra.com will understand it. And the parentheses makes it clear what is inside the square root.)
a. T = 10c; v = 9m/sec:
I'm assuming that the "c" means Celcius/Centigrade.
Replacing the square root of the perfect square, 9:
Now you just simplify (according to PEMDAS, of course). Inside the first parentheses we multiply first:
Adding/subtracting the like terms in both sets of parentheses:
Multiply:
W = 33 - 723.35
Subtracting:
W = -690.35
What does "W" represent? Is it possible for it to have a negative value? If not, then the equation is still incorrect.
I'm going to skip part b and go on to part c. After seeing parts a and c solved I hope you will be able to do part b on your own.
c. T=-10c, v=20/sec
This time the square root does not turn into a whole number (since 20 is not a perfect square). But it will simplify:
Adding/subtracting the like terms in both sets of parentheses:
Distribute the 43:
Subtract the expression in the parentheses:
Adding like terms:
This is an exact expression for the answer. For a decimal approximation of the answer, then we need to use a calculator on the square root:
W = 443.65 - 860*2.23606798
Multiply:
W = 443.65 - 1923.01846065
Subtract:
W = -1479.36846065
So W is approximately -1480.
I hope that from parts a & c you are now able to do part b on your own.
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