SOLUTION: The width of a photo is 5 inches less than its length. A border of 2 inches is placed around the photo. The area covered by the photo and its border is 150 square inches. Find the

Algebra ->  Algebra  -> Square-cubic-other-roots -> SOLUTION: The width of a photo is 5 inches less than its length. A border of 2 inches is placed around the photo. The area covered by the photo and its border is 150 square inches. Find the       Log On

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Question 591584: The width of a photo is 5 inches less than its length. A border of 2 inches is placed around the photo. The area covered by the photo and its border is 150 square inches. Find the dimensions of the photo itself.
Answer by mananth(12270) About Me  (Show Source):
You can put this solution on YOUR website!
length = x
width = x-5
border = 2in
length including border = x+2+2=x+4
width including border = x-5 +2+2= x-1
Area = L*W
Area = (x+4)(x-1)=150
x^2+3x-4=150
x^2+3x-154=0
x^2+14x-11x-154=0
x(x+14)-11(x+14)=0
(x+14)(x-11)=0
x= 11 which is positive.
length = 11 inches
width = 11-5 = 6
CHECK
(11+4)(6+4)=150