# SOLUTION: The width of a photo is 5 inches less than its length. A border of 2 inches is placed around the photo. The area covered by the photo and its border is 150 square inches. Find the

Algebra ->  Algebra  -> Square-cubic-other-roots -> SOLUTION: The width of a photo is 5 inches less than its length. A border of 2 inches is placed around the photo. The area covered by the photo and its border is 150 square inches. Find the       Log On

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 Question 591584: The width of a photo is 5 inches less than its length. A border of 2 inches is placed around the photo. The area covered by the photo and its border is 150 square inches. Find the dimensions of the photo itself.Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!length = x width = x-5 border = 2in length including border = x+2+2=x+4 width including border = x-5 +2+2= x-1 Area = L*W Area = (x+4)(x-1)=150 x^2+3x-4=150 x^2+3x-154=0 x^2+14x-11x-154=0 x(x+14)-11(x+14)=0 (x+14)(x-11)=0 x= 11 which is positive. length = 11 inches width = 11-5 = 6 CHECK (11+4)(6+4)=150