SOLUTION: Lesson topic-Factoring differences of squares Question-Solve equation by factoring. 36x-16x^3= 9x^2-4x^4 .. i know you have to put it in descending form : 36x-16x^3-9x^2+36x then
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Question 575965: Lesson topic-Factoring differences of squares Question-Solve equation by factoring. 36x-16x^3= 9x^2-4x^4 .. i know you have to put it in descending form : 36x-16x^3-9x^2+36x then you find the GCF:x(4x^3-16x^2)(-9x+36) then what?? pleaseeeee with cherry on top help!
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Add 
to both sides:
Group and factor out the GCF from each group:
\ -\ 4x\left(4x^2\ -\ 9\right)\ =\ 0)
Note that the two quadratic binomials are equal, so:
\left(4x^2\ -\ 9\right)\ =\ 0)
Factor the difference of two squares:
\left(2x\ -\ 3\right)\left(2x\ +\ 3\right)\ =\ 0)
Factor the GCF out of the quadratic binomial:
\left(2x\ -\ 3\right)\left(2x\ +\ 3\right)\ =\ 0)
Finally apply the Zero Product Rule to solve for each of the four expected roots.
John
My calculator said it, I believe it, that settles it
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