SOLUTION: Please help w/ the following: Solve(3x+3)^2=16 Thank you.

Algebra.Com
Question 55250: Please help w/ the following:
Solve(3x+3)^2=16
Thank you.

Answer by funmath(2933)   (Show Source): You can put this solution on YOUR website!
Solve
Use the square root property:
For any real number c, if , then or .


or
or
or
or
or
:
Check:
if x=1/3



x=1/3 checks out.
if x=-7/3



x=-7/3 also check out, so we're right!!!
Happy Calculating!!!

RELATED QUESTIONS

Please help w/ the following: Solve x^2/2 - 5x/4 = -3/4 Thank... (answered by funmath)
Please help w/ the following: Solve x+2/3 - x-2/5 =4 Thank... (answered by Earlsdon)
Please help w/ the following: Solve: 4x^2+x=3 Thank... (answered by checkley71)
Please help w/ the following: e^-3x=3.1 Thank... (answered by funmath)
Please help me solve the following equations: 50) a+4/2 = a+4/a 64) 4w-1/3w+6 - (answered by madhujiithcharu@yahoo.co.in)
Please help w/ the following: 2x^-2+3x^-1+1=0 Thank... (answered by funmath)
Please help w/ the following: Multiply: [{x+2}^3] Thank... (answered by tutorcecilia,funmath)
Please help w/ the following: Factor: 2x^4+7x^3-29x^2-112x-48 Thank You. (answered by stanbon)
Solve (w-3)/(w+2)=(6-w)/(w-12) Please I nedd help with this! Thank... (answered by math-vortex)