SOLUTION: leave a non-perfect square under the radical sign: 3n^2-2n^2+8=89. how do I solve something like this?
Algebra.Com
Question 550647: leave a non-perfect square under the radical sign: 3n^2-2n^2+8=89. how do I solve something like this?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
3n^2-2n^2+8=89
3n^2-2n^2=89-8
n^2=81
n=+-sqrt(81)
n=9 or n=-9
RELATED QUESTIONS
leave a non-perfect square under the radial sign: x^2+23=144. what is a non-perfect... (answered by jim_thompson5910)
I cannot understand how to solve the quadratic equation: -1+3x^2=2x
I need to use the... (answered by checkley77,solver91311)
I am having such a time understanding how to solve...
w^4 - 20w^2 - 2 = 0.
It is not... (answered by solver91311)
I am not getting this at ALL :( I am a complete math IDIOT, and I really need the steps... (answered by solver91311)
How do I solve using the square root and radical sign?... (answered by stanbon)
the problem is radical 3+2n + radical 2-2n =3, when i type radical it means the
3+2n... (answered by ankor@dixie-net.com)
2 Math problems.. Having serious trouble. I really appreciate it!!!
1. Divide. Then... (answered by nyc_function)
so i was using the practice questions and the problem was
1xsquared+ -7x +10=0
now (answered by ewatrrr)
how do i solve?
The product of 5 and 2 less than triple a number equals the product of 7 (answered by ewatrrr,DrBeeee)