SOLUTION: One leg of a right triangle is one in. more than twice the other leg. the hypotenuse is square root 29 in long. Find the lengths of the legs

Question 524147: One leg of a right triangle is one in. more than twice the other leg. the hypotenuse is square root 29 in long. Find the lengths of the legs
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
one leg = x
other leg = 2x+1
hypotenuse = sqrt(29)
Using Pythagoras theorem
leg1^2+leg^2=hyp^2
x^2+(2x+1)^2=(sqrt(29))^2
x^2+4x^2+4x+1=29
5x^2+4x-28=0
Find the roots of the equation by quadratic formula

a= 5 ,b= 4 ,c= -28
b^2-4ac=
b^2-4ac= 16 - 560
b^2-4ac= 576 = 24

x1=( -4 + 24 )/ 10
x1= 2
x2=( -4 -24 ) / 10
x2= -2.8
Ignore negative value
one leg = 2
other leg =>2x+1=>5
m.ananth@hotmail.com

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