SOLUTION: x^-75=0. Im having a hard time with this problem please help solve
Algebra.Com
Question 517165: x^-75=0. Im having a hard time with this problem please help solve
Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x^-75=0
---
(1/x)^75 = 0
(1/x) = 0
x is undefined
================
Cheers,
Stan H.
===========
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
I'm presuming you mean:
(Note: ^ does NOT mean "squared", it means "raised to the power of" the expression following the ^. If you meant 
as I suspect, then you needed to have written x^2 - 75 = 0)
This is nothing more than the difference of two squares. But 75 is not a perfect square, you complain. Well, yes it is, sort of. It is the perfect square of 
, right?
So re-write the equation:
^2\ =\ 0)
Or better yet, recognize that 
and then write:
^2\ =\ 0)
Then follow the conjugate factors of the difference of two squares pattern, i.e. (a\ -\ b))
, to factor your LHS:
\left(x\ -\ 5\sqrt{5}\right)\ =\ 0)
And then just apply the Zero Product Rule.
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
will you please help me with this equation? im having a hard time figuring it out.... (answered by stanbon)
Im really having a hard time with this question..Please help
sqrt3 -... (answered by htmentor)
Im having a hard time with this problem... (answered by Alan3354)
I am having a hard time with this problem can you please help?... (answered by stanbon)
x-2y=1 i do not get this at all im having a very hard time graphing equations please help
(answered by ReadingBoosters)
Solve. X^2 = -6x.
I am having a hard time with this problem and need some help.... (answered by stargrl12566)
iam having a bit of a hard time with this problem help with be greatly thankful
(675... (answered by Alan3354)
Can I also have help with this one...
solve for x and y for x-y=4 and x+y=4
I am... (answered by navytutor)
Having a real hard time with this...please help!
Solve system of equation word problem (answered by stanbon)
