SOLUTION: find two consecutive positive integers such that the sum of their square is 85.

Question 50398: find two consecutive positive integers such that the sum of their square is 85.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
two consecutive positive integers such that the sum of their square is 85
-----------
Let 1st be "x".
Then 2nd is "x+1".
EQUATION:
x^2+(x+1)^2=85
x^2+x^2+2x+1=85
2x^2+2x-84=0
Divide thru by 2 to get:
x^2+x-42=0
Factor as follows;
(x+7)(x-6)=0
x=6 is the positive answer and the 1st number
x+1= 7 is the 2nd number.
Cheers,
Stan H.
RELATED QUESTIONS
Find two consecutive positive integers such that the sum of their square is... (answered by stanbon)

find two consecutive positive integers such that the sum of their square is... (answered by checkley75)

Number Problem. Find two consecutive positive integers such that the sum of their square... (answered by timmy1729,bucky)

Find two consecutive positive integers such that the sum of their squares is 85. (answered by xcentaur)

Find two consecutive positive integers such that the sum of their squares is... (answered by Nate)

Find two consecutive positive integers such that the sum of their squares is... (answered by checkley71)

Number problems. Find two consecutive positive integers such that the sum of their... (answered by checkley75)

Find two consecutive positive integers such that the sum of their squares is 85. Thank (answered by Nate)

Number problems. Find two consecutive positive integers such that the sum of their... (answered by jim_thompson5910)